设3阶行列式D3的第2列元素分别为1,-2,3,对应的代数余子式分别为-3,2...答:奇数行单元格数值之和 =a1+a3+a5+a7+a9 因为,mod(row(a1:a10),2)=mod({1,2,3,4,5,6,7,8,9,10},2)={1,0,1,0,1,0,1,0,1,0} 所以,sumproduct(mod(row(a1:a10),2),a1:a10)=sumproduct({1,0,1,0,1,0,1,0,1,0},a1:a10)=1*a1+0*a2+1*a3+0*a4+……+1*a9...