c语言:输入一个日期,包括年月日。用/隔开,计算这个日期是这一年的第...答:31,28,31,30,31,30,31,31,30,31,30,31};scanf("%d/%d/%d",&year,&month,&day);if((year%4==0&&year%100)||year%400==0) a[2]=29;for(i=0;i<=month-1;i++) n+=a[i];printf("这个日期是%d年的第%d天。
...输入某年某月某日,计算出这一天是该年的第几天?该怎么解答啊_百度...答://输入年月日,输出是该年第几天 include<stdio.h> int sum(int month,int day){ int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};int i;for(i=1;i<month;i++)day+=days[i];return(day);} int leap(year){ int leap=0;if((year%4==0&&year%100!=0)||(yea...
c++ 求输入年月日信息,输出这一天是这一年的第几天答:int day; //日 }date; //声明实体日期date int main(){ int i,days; //设输入日期在该年中为第days天 //每年12个月的天数存放在数组里,2月初始为平年 int day_tab[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};//输入年月日 cout<<"input year:"<<endl;cin>>date....
C++程序:给出年月日,计算该日是该年的第几天答:void main(){ int year, month, day;int days;printf("请输入日期(年,月,日):");scanf("%d, %d, %d", &year, &month, &day);printf("%d年%d月%d日", year, month, day);days = sum_day(month, day);if(leap(year) && month>=3)days = days + 1;printf("是该年的第%d...