高数二重积分,谢谢答:1、原式=∫(0,1)dx∫(0,x)√(x^2-y^2)dy =∫(0,1)dx*[(x^2/2)*arcsin(y/x)+(y/2)*√(x^2-y^2)]|(0,x)=∫(0,1)(π/4)*x^2dx =(π/12)*x^3|(0,1)=π/12 2、原式=∫(0,1)dy∫(0,√y)xy/√(1+y^3)dx =∫(0,1)dy*[(yx^2)/2√(1+y^3...
高数,二重积分,我需要详细步骤,谢谢(๑•ั็ω•็ั...答:积分域 D 的面积 σ = ∫<0, 1> x^2dx = 1/3 f(x, y) = xy + A 两边在 D 上积分,得 A = ∫∫<D>xydxdy + Aσ = ∫<0, 1>xdx∫<0, x^2>ydy + A/3 = (1/2)∫<0, 1>x^5dx + A/3 = 1/12 + A/3 2A/3 = 1/12, A = ∫∫<D>f(x, y)dxdy ...