python循环,从m个数组中取n个数组,急求代码!答:/usr/bin/python3.4# -*- coding: utf-8 -*-import random# 原数组arr = [['a', 1], ['a', 3], ['c', 1], ['c', 3], ['d', 1], ['d', 3]]newarr = []for i in range(2): # 生成随机数 num = random.randint(0, len(arr) - 1) newarr.append...
python如何一次性取出多个随机数答:import random[random.randint(0,100) for _ in range(10)]#[57, 93, 22, 55, 41, 64, 47, 32, 93, 61]range函数输入不同的值,可以设置需要生成随机数的个数,上面的例子中生成了10个随机数。
Python创建一个一维列表,列表包含n个元素,n由键盘输入,列表元素由1...答:代码如下,仅供参考:from random import randintamount = int(input("随机数数量:"))result = [randint(1,100) for i in range(amount)]print(result)输入:10 输出:[2, 65, 58, 24, 15, 12, 38, 24, 18, 79]