C语言 求方程aX^2+bX+c=0解,其中a.b.c由键盘输入。若方程无实根,输出没...答:include <stdio.h> include <math.h> void main(){ float a,b,c;printf("input a,b,c:");scanf("%f%f%f",&a,&b,&c);if (b*b-4*a*c>=0){ if (b*b-4*a*c)\ printf("x1=%.2f,x2=%.2f",(-b+sqrt(b*b-4*a*c))/(2*a),(-b-sqrt(b*b-4*a*c))/(2*a)...
若有随机实数a,b,c,求方程ax²+bx+c=0有解的概率答:利用几何概型,设全集为U,b^2>=4ac所代表的空间区域为V,所求即|U∩V|/|U|=|U∩V|/8,绝对值代表体积。剩下的就是积分了。先积c:即给定a,b,求f(a,b),表示c可取范围的“长度”。若a>0,f(a,b)=min{2,b^2/(4a)+1};若a=0,f(a,b)=2;若a<0,f(a,b)=min{2,...
从主函数中输入ax2+bx+c=0的a、b、c参数,用函数求出当b2-4ac大于等于0...答:void main(){ double a,b,c,x1,x2;printf("please input the a,b,c:");scanf("%lf,%lf,%lf",&a,&b,&c);if(P(a,b,c)>=0){x1=(-b+sqrt(P(a,b,c)))/(2*a);x2=(-b-sqrt(P(a,b,c)))/(2*a);printf("x1=%lf,x2=%lf",x1,x2);}else printf("error!")...