用C语言编写一个程序输出任意时间下一秒的时间答:{ YEAR,MONTH,DAY,HOUR,MINUTE,SEC,MAX,};define DUMMY 0 const char *g_apcCnName[MAX]={"年","月","日","时","分","秒"};int isLeapYear(int iYear){ return ((iYear%4==0&&iYear%100!=0)||iYear%400==0);} int main(){ int i;int aiTime[MAX]={0};int aiTimeM...