任意输入三个整数,求他们的和,平均值,最大值,最小值答:);scanf("%d",&a);scanf("%d",&b);scanf("%d",&c);sum=a+b+c;average=sum/3.0;max=min=a;if (b>max) max=b;if (c>max) max=c;if (b<min) min=b;if (c<min) min=c;printf("它们的和为%d,平均数为%lf,最大值为%d,最小值为%d。",sum,average,max,min);} ...
C语言:从键盘输入三个实数,求出其中最大值和最小值答:include<stdio.h>int main(){float a,b,c,max,min; scanf("%f%f%f",&a,&b,&c); max=min=a; if(b>max)max=b; else if(b<min)min=b; if(c>max)max=c; else if(c<min)min=c; printf("max=%g\nmin=%g\n",max,min); return 0;} ...
c语言求 输入三个数输出其最大值和最小值中间用逗号隔开答:include <stdio.h>int main(void){int a, b, c,max,min;scanf("%d%d%d", &a, &b,& c);max = a;min = a;if (max < b)max = b;if (max < c)max = c;if (min > b)min = b;if (min > c)min = c;printf("%d,%d", max, min);return 0;} ...
C语言求三个数据中最小值用带参数的宏实现答:int a,b,c; scanf("%d%d%d",&a,&b,&c); printf("min:%d\n",min(min(a,b),c)); return 0;}宏定义min(x,y)求x,y中较小的数,这里的三目运算目注意要括号 然后输出叠加两个min 当然宏定义也可以带三个参数,但是就写得比较长,不易阅读 作答不易,望采纳 ...
关于C语言的问题,求三个数中的最小值。答:include<stdio.h> void main(){ int a,b,c,z;printf("请输入任意三个数:\n");scanf("%d,%d,%d",&a,&b,&c);if(a<b)z=a;else z=b;if(c<z)z=c;//printf("%d\n",z); //去掉 //else //去掉 printf("%d\n",z);}// }修改为英文下的} ...