找出1000以内的所有完数python答:求1000以内的完数 for i in range(1, 1001):sum_list = []for j in range(1, i):if i % j:continue else:sum_list.append(j)if sum(sum_list) == i:print("its factors are", sum_list)print(i)--- its factors are [1, 2, 3]6 its factors are [1, 2, 3, 4, 6, ...
输出1000之内的全部“完数”,要求每行输出五个,并统计完数的个数的...答:include "stdio.h"int main(int argc,char *argv[]){int n,m,k,i,s,t;for(s=k=0,n=4;n<1000;n++){for(m=1,t=n/2,i=2;i<=t;i++)if(n%i==0)m+=i;if(m==n){printf(++k%5 ? "%d " : "%d\n",n);s++;}}if(k%5)printf("\n");printf("A total of %d....