第1个回答 2012-12-29
You are a lucky guy, I'm free tonight.
The first equation's code below:
\begin{displaymath}
K\bigg[ \sum_{j\in\mathcal{N}_{i}}sgn(x_{j}-x_{i}) \bigg]= \left\{ \begin{array}{ll}
\{\# \mathcal{N}_{i}^+-\# \mathcal{N}_{i}^-\}& if x_{i}\neq x_{j} \quad \forall j \in \\
\{\# \mathcal{N}_{i}^+-\# \mathcal{N}_{i}^-\}+[-\# \mathcal{N}_{i}^0,\# \mathcal{N}_{i}^0]& otherwise.\\
\end{array} \right.
\end{displaymath}
The last equation:
\begin{displaymath}
\overset{\dot{\sim}}{V}\subseteq \cap_{\xi \in \partial V} \xi^T \left\{ \begin{array}{l}
K[f_{1}]+\alpha K\big[ \sum_{j \in \mathcal{N}_{1}} sgn(x_{j}-x_{i})\big] \\
\vdots \\
K[f_{n}]+\alpha K\big[ \sum_{j \in \mathcal{N}_{n}} sgn(x_{j}-x{i})\big]
\end{array} \right\}
\end{displaymath}
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