#include <stdio.h>main(){ union { short i[2]; long k; char c[4]; }r,*s=&r; s->i[0]=0x39; s->i[1]=0x38; printf("%x\n",s->c[0]);}已知字符0的ASCII码值的十进制数是48,且数组的第0个元素在低位。以上程序的运行结果是__________(俺滴共用体这块学的不咋地。。这道题拿过来就只知道r是短整型的。。望高手详解~~~多谢多谢!!)