C语言 编写一个一维数组求平均值的函数，在主函数中调用。要求数组名做参数

Question

如题所述

Answer 1

#include<stdio.h>
const int N=3000;
int n;
double array[N];
double getAverage(double a[])
{
int i;
double sum=0;
for(i=0;i<n;i++)sum+=a[i];
return sum/n;
}

int main()
{
int i;
printf("输入数组的元素个数 n :\n");
scanf("%d",&n);
printf("依次输入n个元素：\n");
for(i=0;i<n;i++)scanf("%lf",&array[i]);
printf("平均值:\n");
printf("%.3lf\n",getAverage(array));
return 0;
}

Answer 2

int average(int *a,int n)
{
if(n==0)return 0;
int sum=0,i=0;
for(i;i<n;i++)
sum+=a[i];
return sum/n;
}
int main()
{
int arr[5]=;
printf("%d",sum(arr,5));
return 0;
}

Answer 3

int Avg(int * Arr, int ArrSize){
int i,sum = 0;
for(i=0;i<ArrSize;i++){
sum += Arr[i];
}
return sum/ArrSize;
}本回答被提问者和网友采纳

Answer 4

int average(int *a,int n)
{
if(n==0)return 0;
int sum=0,i=0;
for(i;i<n;i++)
sum+=a[i];
return sum/n;
}
int main()
{
int arr[5]=;
printf("%d",sum(arr,5));
return 0;
}