急，用C语言编写，求1到100内不能被3整除的数的和，用CONTINUE完成

Question

如题所述

Answer 1

#include<stdio.h>int main()
{
int i,s=0;for(i=1;i<=100;i++){if(i%3==0)continue;s+=i;}printf("%d\n",s);return 0;}

Answer 2

#include <stdio.h>int main()
{
int x,sum = 0;
for (x=1;x<=100;x++)
{
if (x%3!=0)
{
sum +=x;
}
}
printf("sum = %d\n",sum);
return 0;
}//给你个参考

Answer 3

#include <stdio.h>
#include <stdlib.h> int main()
{
int i,s=0;
for(i=1;i<=100;i++)
{
if(i%3==0)
{
continue;
}
s+=i;
}
printf("%d\n",s);
system("pause");
return 0;
}

Answer 4

int sum=0;for(int i=0;i<100;i++){if(i/3==0){
sum = sum + i;
}else
{
continue;}}
Console.WriteLine("1到100内不能被3整除的数的和：{0}",sum);
Console.ReadLine();

Answer 5

int sum=0;for(int i =1;i<100;i++){if(i%3!=0){sum+=i;}else{continue;}}