（C语言编程）用一维数组求10个数的平均值

Question

如题所述

Answer 1

#include<stdio.h>
main()
{ int a[10] ,sum=0;
int avg;
for(int i=0;i<10;i++)
{
scanf("%d",a[i]);
sum=a[i]+sum;
}
avg=sum/10;
printf("%d",avg);
}

Answer 2

main()
{
int a[10],sum=0;
for(i=0;i<10;i++){scanf("%d",&a[i]);sum+=a[i];}
printf("%.2f\n",sum/10.0);
}

Answer 3

int i,a[10];
float ave;
printf("input date:");
for(i=0;i<10;i++)
scanf("%d",a[i]);
for(i=0;i<10;i++)
s=s+a[i];
ave=s/10;

Answer 4

#include <stdio.h>
int main()
{
int a[ 10 ] = { 0, 5, 6, 7, 8, 9, 12, 13, 14, 1};
int pingjunzhi;
int he = 0;
for( int i = 0; i<10; ++i )
{
he += a[ i ] ;
}
pingjunzhi = he / 10;
printf("平均数是%d\n", pingjunzhi);
return 0;
}

Answer 5

#include<stdio.h>
main()
{
int a[10],sum=0;
double avg;
for(int i=0;i<10;i++)
scanf("%d",a[i]);
for(int i=0;i<10;i++)
sum+=0;
avg=sum/10;
printf("%lf",avg);
}本回答被网友采纳