用c语言编写输出3*4的矩阵,求最后一个最小值并显示行号和列号?

Question

如题所述

Answer 1

#include<stdio.h>

int main() {
const unsigned row=3, col=4;//定义行列数
unsigned minx, miny;//最小值的行列
int min;//最小值
int nums[row][col];
for (unsigned i = 0; i < row; i++)//录入数据
{
for (unsigned j = 0; j < col; j++)
{
scanf("%d",&nums[i][j]);
}
}
min = nums[0][0];//初始化最小值为第一行第一列的数
minx = 1;
miny = 1;
for (unsigned i = 0; i < row; i++)//遍历数组找出最小值
{
for (unsigned j = 0; j < col; j++)
{
if (nums[i][j] <= min)
{
min = nums[i][j];
minx = i+1;
miny = j+1;
}
}
}
printf("最小值为:%d，位于第%u行%u列", min, minx, miny);//输出数据
return 0;
}追问

虽然我已解决 还是很谢谢你哈