python，如何遍历一个目录，输出所有文件名

Question

如题所述

Answer 1

import os

def iterbrowse(path):
    for home, dirs, files in os.walk(path):
        for filename in files:
            yield os.path.join(home, filename)


for fullname in iterbrowse("/home/bruce"):
    print fullname

Answer 2

#coding=utf-8
'''
Created on 2014-11-14

@author: Neo
'''
import os

def GetFileList(dir, fileList):
    newDir = dir
    if os.path.isfile(dir):
        fileList.append(dir.decode('gbk'))
    elif os.path.isdir(dir):  
        for s in os.listdir(dir):
            #如果需要忽略某些文件夹，使用以下代码
            #if s == "xxx":
                #continue
            newDir=os.path.join(dir,s)
            GetFileList(newDir, fileList)  
    return fileList

list = GetFileList('D:\\workspace\\PyDemo\\fas', [])
for e in list:
    print e

result:

D:\workspace\PyDemo\fas\file1\20141113\a.20141113-1100.log

D:\workspace\PyDemo\fas\file1\20141113\a.20141113-1101.log

D:\workspace\PyDemo\fas\file1\20141113\a.20141113-1140.log

D:\workspace\PyDemo\fas\file2\20141113\a.20141113-1100.log

D:\workspace\PyDemo\fas\file2\20141113\a.20141113-1101.log

D:\workspace\PyDemo\fas\file2\20141113\a.20141113-1140.log

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