当x<=0时
f(x)=x+2>=x^2, x^2-x-2=(x-2)(x+1)<=0,-1<=x<=2
又x<=0, 所以-1<=x<=0
当x>0时
f(x)=-x+2>=x^2, x^2+x-2=(x+2)(x-1)<=0, -2<=x<=1
又x>0，所以0<x<=1
综合这两个情况可知：-1<=x<=1，所以选A
f(x)=x+2>=x^2, x^2-x-2=(x-2)(x+1)<=0,-1<=x<=2
又x<=0, 所以-1<=x<=0
当x>0时
f(x)=-x+2>=x^2, x^2+x-2=(x+2)(x-1)<=0, -2<=x<=1
又x>0，所以0<x<=1
综合这两个情况可知：-1<=x<=1，所以选A
温馨提示：答案为网友推荐，仅供参考
相似回答