求解一个c语言问题，输入年月日输出第几天，但日子不会加，急求。。求解。。。

Question

# include<stdio.h>
int DayofYear(int year, int month, int day);
static int dayTab[2][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}};
main()
{
printf("Enter year, month, day:\n");
int day, month, year;
scanf("%d%d%d",&year,&month,&day);
DayofYear(year, month, day);
printf("%d",day);

}
int DayofYear(int year, int month, int day)
{
int i, leap;
leap = ((year % 4==0)&&(year % 100!=0)||(year % 400==0));
for(i=1;i<=month;i++)
{
day = day + dayTab[leap][i];
}
return day;
}

Answer 1

1、不改其他情况下
只改：
printf("%d",DayofYear(year, month, day));
和
for(i=1;i< month;i++) //如果 i可以等于month，会多出这个月的天数

2、引用

#include<iostream>
using namespace std;
#include<stdio.h>
int DayofYear(int year, int month, int &day); //引用时，才会改变原day 里面的值
static int dayTab[2][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}};
main()
{
printf("Enter year, month, day:\n");
int day, month, year;
scanf("%d%d%d",&year,&month,&day);
DayofYear(year, month, day);
printf("%d",day);
}
int DayofYear(int year, int month, int &day) //引用时，才会改变原day 里面的值
{
int i, leap;
leap = ((year % 4==0)&&(year % 100!=0)||(year % 400==0));
for(i=1;i< month;i++) //如果 i可以等于month，会多出这个月的天数
{
day = day + dayTab[leap][i];
}
return day;
}

Answer 2

如下修改就好啦！
#include<stdio.h>
int DayofYear(int year, int month, int day);
static int dayTab[2][13]={
{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}};
main()
{
printf("Enter year, month, day:\n");
int day, month, year;
scanf("%d%d%d",&year,&month,&day);
day=DayofYear(year, month, day);
printf("%d",day);
}
int DayofYear(int year, int month, int day)
{
int i, leap;
leap = ((year % 4==0)&&(year % 100!=0)||(year % 400==0));
for(i=1;i<=month;i++){
day = day + dayTab[leap][i];
}
return day;
}本回答被网友采纳

Answer 3

其实不需要定义二维数组，通过判断year是否为闰年，来判断是否需要多加1年

Answer 4

好难

Answer 5

for( i = 1; i < month; i++ )