C++中使用cout << endl 换行问题

Question

刚接触C++，编了一个小程序。
以度、分、秒输入纬度，以度输出，程序如下。
#include "stdafx.h"
#include <iostream>
int main()
{
using namespace std;
const double zhuanhuan = 60.0;
int degrees,minutes,seconds;
double Degrees;
cout << "Enter a latitude in degrees, minutes, and seconds: \n";
cout << "First, enter the degrees: ";
cin >> degrees;
cout << endl << "Next, enter the minutes of arc: ";
cin >> minutes;
cout << endl << "Finally, enter the seconds of arc: ";
cin >> seconds;
cout << endl << degrees << " degrees, " << minutes << " minutes, " << seconds << " seconds = ";
Degrees = (seconds / zhuanhuan + minutes) / 60 + degrees;
cout << Degrees << " degrees\n";
cout << "Press any key to return.";
cin.get();
cin.get();
return 0;
}

为什么输出中多空了几行？
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Answer 1

比如First ,enter the degrees: 37这一行——你输入37时已经打入一个回车了，下面接着cout << endl << "Next, enter the minutes of arc: ";中的<<endl还要回车一次，就两次了。把类似cout << endl << "Next, enter the minutes of arc: ";中的<< endl删除即可。