求弧度：已知0° 30° 45° 60° 90° 180° 270° 360°…分别求出它们弧度

Question

如题所述

Answer 1

就是用度数÷180后面跟个π就行了
0°=0
30°=π/6
45°=π/4
60°=π/3
90°=π/2
180°=π
270°=3π/2
360°=2π
n° = (n/180)π

Answer 2

0°=0
30°=π/6
45°=π/4
60°=π/3
90°=π/2
180°=π
270°=3π/2
360°=2π

Answer 3

30° =π/6,
45°= π/4,
60°= π/3,
90°= π/2,
180°= π,
270°=3 π/2,
360°=2π

Answer 4

呵呵，是不是要帮你算呀？懒人
分别是（保留三位小数)
0,0.524,0.785,1.047,1.571,3.142,4.712,6.283