第1个回答 2008-10-24
1.解:
5abc-{2a²-[3ab-(4ab²-a²b)]}
=5abc-{2a²-[3ab-4ab²+a²b]}
=5abc-{2a²-3ab+4ab²-a²b}
=5abc-2a²+3ab-4ab²+a²b
当a=-2,b=-1,c=3时
5abc-2a²+3ab-4ab²+a²b
=5×-2×-1×3-2×(-2)²+3×-2×-1-4×-2×(-1)²+(-2)²-1
=30-2×4+6-4×-2×1+4-1
=30-8+6-(-8)+3
=28+8+3
=39
2.解:-(3a-4)-(a²-3a+5)+(4a-a²)
=-3a+4-a²+3a-5+4a-a²
=-2a²-1
当a=-1/3